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Oracle Introduction to Oracle9i: SQL Sample Questions:
1. Examine the description of the STUDENTS table:
Which two aggregate functions are valid on the START_DATE column? (Choose two)
A) AVG (start_date)
B) SUM (start_date)
C) AVG (start_date, end_date)
D) COUNT (start_date)
E) MIN (start_date)
F) MAXIMUM (start_date)
2. The EMPLOYEES table contains these columns:
You need to write a query that will produce these results:
1.Display the salary multiplied by the commission_pct.
2.Exclude employees with a zero commission_pct.
3.Display a zero for employees with a null commission value.
Evaluate the SQL statement:
SELECT LAST_NAME, SALARY*COMMISSION_PCT
FROM EMPLOYEES
WHERE COMMISSION_PCT IS NOT NULL;
What does the statement provide?
A) One of the desired results
B) All of the desired results
C) Two of the desired results
D) An error statement
3. Examine the structure of the EMP_DEPT_VU view:
Which SQL statement produces an error?
A) SELECT department_id, SUM(salary)
FROM emp_dept_vu
GROUP BY department_id;
B) None of the statements produce an error; all are valid.
C) SELECT job_id, SUM(salary)
FROM emp_dept_vu
WHERE department_id IN (10,20)
GROUP BY job_id
HAVING SUM(salary) > 20000;
D) SELECT *
FROM emp_dept_vu;
E) SELECT department_id, job_id, AVG(salary)
FROM emp_dept_vu
GROUP BY department_id, job_id;
4. Exhibit:
Examine the data in the EMPLOYEES table.
Examine the subquery:
SELECT last_name FROM employees WHERE salary IN (SELECT MAX(salary) FROM employees GROUP BY department_id);
Which statement is true?
A) The SELECT statement does not work because the GROUP BY clause should be in the
main query and not in the subquery.
B) The SELECT statement does not work because there is no HAVING clause.
C) The SELECT statement is syntactically accurate.
D) The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.
5. The CUSTOMERS table has these columns:
The CUSTOMER_ID column is the primary key for the table.
You need to determine how dispersed your customer base is.
Which expression finds the number of different countries represented in the CUSTOMERS table?
A) COUNT(DISTINCT (UPPER(country_address)))
B) COUNT(DIFF(UPPER(country_address)))
C) COUNT(UPPER(country_address))
D) COUNT(UNIQUE(UPPER(country_address)))
E) COUNT DISTINCT UPPER(country_address)
Solutions:
| Question # 1 Answer: D,E | Question # 2 Answer: A | Question # 3 Answer: B | Question # 4 Answer: C | Question # 5 Answer: A |


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